Projectile Motion Analysis of an Upward Thrown Ball

Projectile Motion Analysis of an Upward Thrown Ball

In this article, we will analyze the motion of a ball thrown directly upward using fundamental principles of physics and kinematic equations. We will derive the time the ball remains in the air and explore the underlying physics involved in such motion.

Introduction to Projectile Motion

Projectile motion refers to the motion of an object that is projected into the air and subject to gravitational acceleration. In the absence of air drag, the only force acting on the ball is gravity, which causes a constant downward acceleration of approximately 9.81 m/s2.

Equation of Motion for the Ball

The height (ht) of the ball as a function of time (t) is given by:

$h_t h_0 v_0 t - frac{1}{2} g t^2$

where:

$h_t$ is the height of the ball at time $t$. $h_0$ is the initial height (3.5 m in this case). $v_0$ is the initial velocity (15 m/s in this case). $g$ is the acceleration due to gravity (9.81 m/s2). $t$ is the time in seconds.

When the ball hits the ground, $h_t 0$. Therefore, we need to solve the equation for time $t$ when $h_t 0$:

$0 3.5 15t - frac{1}{2} times 9.81 times t^2$

Rearranging this equation, we get:

$4.905t^2 - 15t - 3.5 0$

Solving the Quadratic Equation

To solve the quadratic equation $4.905t^2 - 15t - 3.5 0$, we use the quadratic formula:

$t frac{-b pm sqrt{b^2 - 4ac}}{2a}$

where $a 4.905$, $b -15$, and $c -3.5$. First, we calculate the discriminant:

$b^2 - 4ac (-15)^2 - 4 times 4.905 times -3.5$

$ 225 68.07 293.07$

Substituting the values into the quadratic formula, we get:

$t frac{15 pm sqrt{293.07}}{2 times 4.905}$

Calculating the square root of 293.07:

$sqrt{293.07} approx 17.1$

Substituting this back into the formula:

$t frac{15 pm 17.1}{9.81}$

Calculating the two possible values for $t$:

$t frac{15 17.1}{9.81} approx frac{32.1}{9.81} approx 3.27 text{ s}$

$t frac{15 - 17.1}{9.81} approx frac{-2.1}{9.81}$ (not physically meaningful since time cannot be negative)

Therefore, the time the ball is in the air is approximately 3.27 seconds.

Summary of Key Points

In this article, we covered the application of kinematic equations to solve projectile motion problems, specifically the motion of a ball thrown upward. We derived the time of flight using the quadratic formula and highlighted the significance of time conventions in physics calculations.

Conclusion

Understanding projectile motion is crucial in various fields, including sports, engineering, and physics. By mastering the application of kinematic equations, one can effectively analyze and predict the motion of objects under gravitational influence.

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