Analysis of Batting Outcomes in Cricket: A Unique Scenario

Cricket is a complex and intriguing sport that often presents unique scenarios. One such scenario arises when 10 batsmen are out in the space of 10 balls. Under the given conditions, if no batsman is dismissed via run out, handling the ball, obstructing the field, etc., but is cleanly dismissed by being bowled, LBW, stumped, or caught, then what will be the status of the remaining batsmen?

Theoretical Scenario

Let's delve into this scenario with a structured approach. Side changes occur once an over ends, and we will calculate the status of the batsmen after the fall of the 10th wicket.

Step-by-Step Breakdown

1. First Over: Assume that the game starts from the first ball of the innings with the first opener at the striker's end and the other at the non-striker's end.

Ball 1: Batsman number 1 gets out (cleanly bowled, LBW, caught, or stumped). Ball 2: Batsman number 3 gets out (cleanly bowled, LBW, caught, or stumped). Ball 3: Batsman number 4 gets out (cleanly bowled, LBW, caught, or stumped). Ball 4: Batsman number 5 gets out (cleanly bowled, LBW, caught, or stumped). Ball 5: Batsman number 6 gets out (cleanly bowled, LBW, caught, or stumped). Ball 6: Batsman number 7 gets out (cleanly bowled, LBW, caught, or stumped).

At this point, the first over is completed, and the side change occurs.

Side change during an over

2. Second Over:

Ball 7: Batsman number 2 gets out (cleanly bowled, LBW, caught, or stumped). Ball 8: Batsman number 9 gets out (cleanly bowled, LBW, caught, or stumped). Ball 9: Batsman number 10 gets out (cleanly bowled, LBW, caught, or stumped). Ball 10: Batsman number 11 gets out (cleanly bowled, LBW, caught, or stumped).

Thus, after 10 balls in the first over, Batsman number 8 remains not out, as the 10th wicket falls with the last batsman getting out.

Theoretical Outcomes

Theoretically, any one of the 11 batsmen can remain not out after the fall of the 10th wicket, as wickets may fall due to being bowled, caught, or run out.

Step-by-Step Example

Ball 1: Batsman number 1 bowls and the non-striker (number 2) gets out (cleanly bowled, LBW, caught, or stumped). Ball 2: The batsman at number 3 comes in and gets out (cleanly bowled, LBW, caught, or stumped). Ball 3: The batsman at number 4 gets out (cleanly bowled, LBW, caught, or stumped). Ball 4: The batsman at number 5 gets out (cleanly bowled, LBW, caught, or stumped). Ball 5: The batsman at number 6 gets out (cleanly bowled, LBW, caught, or stumped). Ball 6: The batsman at number 7 gets out (cleanly bowled, LBW, caught, or stumped). End of 1st Over: Side changes. Ball 7: The batsman at number 2 bowls and Batsman number 1 gets out (cleanly bowled, LBW, caught, or stumped). Ball 8: The batsman at number 9 gets out (cleanly bowled, LBW, caught, or stumped). Ball 9: The batsman at number 10 gets out (cleanly bowled, LBW, caught, or stumped). Ball 10: The batsman at number 11 gets out (cleanly bowled, LBW, caught, or stumped).

This sequence ensures that the batsman at number 8 stays not out.

Conclusion

In conclusion, following this specific set of conditions, after 10 wickets have fallen in 10 balls, the batsman who will remain not out is the 8th batsman. Side changes during the end of the over affect the positioning of the batsmen, but Batsman number 8 stays not out.

FAQ

Question: How does the side change affect the outcome of the scenario?

Answer: The side change does not affect the outcome. The 8th batsman remains not out as the 10th wicket falls, ensuring that he was the last to be put out.

Question: Are there any other possible scenarios for the batsman's status?

Answer: While the scenario specified above results in the 8th batsman remaining not out, theoretically, any batsman could remain not out after the fall of the 10th wicket if the wickets fall in a different order. The main condition is that all 10 wickets must be lost cleanly.